Advertisements
Advertisements
प्रश्न
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 720
Advertisements
उत्तर
log16 = a, log9 = b and log5 = c
log42 = a, log32 = b and log5 = c
2log4 = a, 2log3 = b and log5 = c
`"log"4 = "a"/(2) , "log"3 = "b"/(2) and "log"5` = c
Consider, log720 = log(42 x 32 x 5)
= log42 + log32 + log5
= 2log4 + 2log3 + log5
= `2("a"/2) + 2 ("b"/2) + "c"`
= a + b + c.
APPEARS IN
संबंधित प्रश्न
If log10 8 = 0.90; find the value of : log 0.125
Simplify : log (a)3 ÷ log a
Express the following in terms of log 5 and/or log 2: log125
Express the following as a single logarithm:
`2 "log" 3 - (1)/(2) "log" 16 + "log" 12`
Express the following as a single logarithm:
`2"log"(15)/(18) - "log"(25)/(162) + "log"(4)/(9)`
Express the following as a single logarithm:
`"log"(81)/(8) - 2"log"(3)/(5) + 3"log"(2)/(5) + "log"(25)/(9)`
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log18
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`
Simplify: log a2 + log a-1
Find the value of:
`("log"sqrt(8))/(8)`
