Advertisements
Advertisements
प्रश्न
Find the value of:
`("log"sqrt(8))/(8)`
बेरीज
Advertisements
उत्तर
`("log"sqrt(8))/(8)`
= `("log"2sqrt(2))/(8)`
= `(1)/(8)("log"2 + "log"sqrt(2))`
= `(1)/(8)("log"2 + "log"2^(1/2))`
= `(1)/(8)"log"2 + (1)/(8)"log"2^(1/2)`
= `(1)/(8)"log"2 + (1)/(2)(1)/(8)"log"2`
= `(1)/(8)"log"2 + (1)/(16)"log"2`
= `(2)/(16)"log"2 + (1)/(16)"log"2`
= `(3)/(16)"log"2`.
shaalaa.com
Expansion of Expressions with the Help of Laws of Logarithm
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
