Advertisements
Advertisements
प्रश्न
Find the value of:
`("log"sqrt(8))/(8)`
Advertisements
उत्तर
`("log"sqrt(8))/(8)`
= `("log"2sqrt(2))/(8)`
= `(1)/(8)("log"2 + "log"sqrt(2))`
= `(1)/(8)("log"2 + "log"2^(1/2))`
= `(1)/(8)"log"2 + (1)/(8)"log"2^(1/2)`
= `(1)/(8)"log"2 + (1)/(2)(1)/(8)"log"2`
= `(1)/(8)"log"2 + (1)/(16)"log"2`
= `(2)/(16)"log"2 + (1)/(16)"log"2`
= `(3)/(16)"log"2`.
APPEARS IN
संबंधित प्रश्न
If 3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x, find x.
Given 2 log10 x + 1 = log10 250, find :
(i) x
(ii) log10 2x
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2
If log 27 = 1.431, find the value of : log 9
Prove that : If a log b + b log a - 1 = 0, then ba. ab = 10
If 2 log y - log x - 3 = 0, express x in terms of y.
Express the following in terms of log 2 and log 3: `"log"(225)/(16) - 2"log"(5)/(9) + "log"(2/3)^5`
Write the logarithmic equation for:
V = `(4)/(3)pi"r"^3`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 75
If 2 log y - log x - 3 = 0, express x in terms of y.
