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प्रश्न
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
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उत्तर
Ethanol undergoes intermolecular H-bonding due to the presence of −OH group, resulting in the association of molecules. Extra energy is required to break these hydrogen bonds. On the other hand, methoxymethane does not undergo H-bonding. Therefore, ethanol has a higher boiling point than methoxymethane.
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संबंधित प्रश्न
Give reasons for the following : Boiling point of ethanol is higher in comparison to methoxymethane.
Explain why propanol has higher boiling point than that of the hydrocarbon, butane?
`CH_3-CH_2-Br"Alcoholic KOH"/""> B " HBR"/"">C"Na/Eather"/"">D`, the Compound D is
(A) ethane
(B) propane
(C) n-butane
(D) n-pentane
Account for the following:
CH3CHO is more reactive than CH3COCH3 towards reaction with HCN.
Write a chemical reaction to show that the open structure of D-glucose contains the following :
Five alcohol groups
The correct order of boiling points for primary (1°), secondary (2°) and tertiary alcohol (3°) is:
Which of the following has lowest boiling point?
Arrange the following in order of increasing boiling point:
Ethoxyethane, Butanal, Butanol, n-butane
Assertion (A): Alcohols react both as nucleophiles and electrophiles.
Reason (R): The bond between C–O is broken when alcohols react as nucleophiles.
Select the most appropriate answer from the options given below:
How are the following conversion carried out?
Methyl magnesium bromide →2-Methylpropan-2-ol.
Write a note on Kolbe's reaction
What is esterifications? How is an ester obtained from alcohol or phenol?
How are the following conversions carried out?
Methyl magnesium bromide → 2 -Methylpropan-2-ol.
How is the following conversion carried out?
Methyl magnesium bromide → 2-Methylpropan-2-ol.
How is the following conversion carried out?
\[\ce{Methyl magnesium bromide ->2-Methylpropan-2-ol}\]
