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For the Following Differential Equation, Find the General Solution:- D Y D X = ( 1 + X 2 ) ( 1 + Y 2 ) - Mathematics

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प्रश्न

For the following differential equation, find the general solution:- \[\frac{dy}{dx} = \left( 1 + x^2 \right)\left( 1 + y^2 \right)\]

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उत्तर

We have,

\[\frac{dy}{dx} = \left( 1 + x^2 \right)\left( 1 + y^2 \right)\]

\[ \Rightarrow \frac{1}{\left( 1 + y^2 \right)}dy = \left( 1 + x^2 \right)dx\]

Integrating both sides, we get

\[\int\frac{1}{\left( 1 + y^2 \right)}dy = \int\left( 1 + x^2 \right)dx\]

\[ \Rightarrow \tan^{- 1} y = x + \frac{x^3}{3} + C\]

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पाठ 22: Differential Equations - Revision Exercise [पृष्ठ १४६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Revision Exercise | Q 64.3 | पृष्ठ १४६

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