मराठी

D Y D X = ( X + Y ) 2 - Mathematics

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प्रश्न

\[\frac{dy}{dx} = \left( x + y \right)^2\]

बेरीज
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उत्तर

We have,

\[\frac{dy}{dx} = \left( x + y \right)^2 . . . . . \left( 1 \right)\]

Let `x + y = v`

\[ \Rightarrow 1 + \frac{dy}{dx} = \frac{dv}{dx}\]

\[ \Rightarrow \frac{dy}{dx} = \frac{dv}{dx} - 1\]

Therefore, (1) becomes

\[ \therefore \frac{dv}{dx} - 1 = v^2 \]

\[ \Rightarrow \frac{dv}{dx} = v^2 + 1\]

\[ \Rightarrow \frac{1}{v^2 + 1}dv = dx\]

Integrating both sides, we get

\[\int\frac{1}{v^2 + 1}dv = \int dx\]

\[ \Rightarrow \tan^{- 1} v = x + C\]

\[ \Rightarrow v = \tan\left( x + C \right)\]

\[ \Rightarrow x + y = \tan\left( x + C \right) \]

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पाठ 22: Differential Equations - Revision Exercise [पृष्ठ १४६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 22 Differential Equations
Revision Exercise | Q 35 | पृष्ठ १४६

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