Advertisements
Advertisements
प्रश्न
Find the missing value:
| Base | Height | Area of Triangle |
| 22 cm | ______ | 170.5 cm2 |
Advertisements
उत्तर
| Base | Height | Area of Triangle |
| 22 cm | 15.5 | 170.5 cm2 |
Explanation:
b = 22 cm
h = ?
Area = `1/2 xx b xx h` = 170.5 cm2
`1/2 xx 22 xx h` = 170.5 cm2
h = `(170.5 xx 2)/22`
h = 15.5 cm
Therefore, the height of such triangle is 15.5 cm.
संबंधित प्रश्न
If P(–5, –3), Q(–4, –6), R(2, –3) and S(1, 2) are the vertices of a quadrilateral PQRS, find its area.
Find the area of the quadrilateral ABCD whose vertices are respectively A(1, 1), B(7, –3), C(12, 2) and D(7, 21).
In each of the following find the value of 'k', for which the points are collinear.
(7, -2), (5, 1), (3, -k)
Find a relation between x and y if the points (x, y), (1, 2) and (7, 0) are collinear.
The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB) = (AE)/(AC) = 1/4`Calculate the area of the ΔADE and compare it with the area of ΔABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles)
Find the angle subtended at the origin by the line segment whose end points are (0, 100) and (10, 0).
Show that the points are the vertices of an isosceles right triangle.
Find the value of x for which points A(x, 2), B(-3, -4) and C(7, -5) are collinear.
Find the value of p for which the points (−5, 1), (1, p) and (4, −2) are collinear.
The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
