Advertisements
Advertisements
प्रश्न
Find the missing value:
| Base | Height | Area of Triangle |
| 22 cm | ______ | 170.5 cm2 |
Advertisements
उत्तर
| Base | Height | Area of Triangle |
| 22 cm | 15.5 | 170.5 cm2 |
Explanation:
b = 22 cm
h = ?
Area = `1/2 xx b xx h` = 170.5 cm2
`1/2 xx 22 xx h` = 170.5 cm2
h = `(170.5 xx 2)/22`
h = 15.5 cm
Therefore, the height of such triangle is 15.5 cm.
संबंधित प्रश्न
The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle.
Prove that the points (2, – 2), (–3, 8) and (–1, 4) are collinear
For what value of x will the points (x, –1), (2, 1) and (4, 5) lie on a line ?
Find the area of the triangle whose vertices are: (2, 3), (-1, 0), (2, -4)
If G be the centroid of a triangle ABC and P be any other point in the plane, prove that PA2+ PB2 + PC2 = GA2 + GB2 + GC2 + 3GP2.
Show that the points A(3, 0), B(6, 4) and C(–1, 3) are the vertices of an isosceles right triangle.
If G(–2, 1) is the centroid of a ΔABC and two of its vertices are A(1, –6) and B(–5, 2), find the third vertex of the triangle.
Prove that the points A(a, 0), B(0, b) and C(1, 1) are collinear, if `(1/a + 1/b) = 1`.
Find the area of the triangle whose vertices are (–8, 4), (–6, 6) and (–3, 9).
In the following figure, if PR = 12 cm, QR = 6 cm and PL = 8 cm, then QM is ______.

