Advertisements
Advertisements
प्रश्न
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (see the given figure). The height AD from A to BC, is 6 cm. Find the area of ΔABC. What will be the height from C to AB i.e., CE?
Advertisements
उत्तर
Area of triangle ABC = `1/2 xx "Base" xx "Height"`
= `1/2 xx BC xx AD`
= `1/2 xx 9 xx 6`
= 27 cm2
Area of triangle ABC = `1/2 xx "Base" xx "Height"`
= `1/2 xx AB xx CE`
`27 = 1/2 xx 7.5 xx CE`
CE = `(27 xx 2)/7.5`
CE = 7.2 cm
APPEARS IN
संबंधित प्रश्न
For what value of k are the points (k, 2 – 2k), (–k + 1, 2k) and (–4 – k, 6 – 2k) are collinear ?
The vertices of a ΔABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB) = (AE)/(AC) = 1/4`Calculate the area of the ΔADE and compare it with the area of ΔABC. (Recall Converse of basic proportionality theorem and Theorem 6.6 related to ratio of areas of two similar triangles)
Find the equation of the line joining (3, 1) and (9, 3) using the determinants.
Find the angle subtended at the origin by the line segment whose end points are (0, 100) and (10, 0).
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
Using integration, find the area of triangle ABC, whose vertices are A(2, 5), B(4, 7) and C(6, 2).
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| 20 cm | 40 cm | ? |
Let ∆ = `|("A"x, x^2, 1),("B"y, y^2, 1),("C"z, z^2, 1)|`and ∆1 = `|("A", "B", "C"),(x, y, z),(zy, zx, xy)|`, then ______.
The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
In the following figure, area of ΔPQR is 20 cm2 and area of ΔPQS is 44 cm2. Find the length RS, if PQ is perpendicular to QS and QR is 5 cm.
