Advertisements
Advertisements
प्रश्न
ΔABC is right angled at A (see the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.
Advertisements
उत्तर
Area = `1/2 xx "Base" xx "Height"`
Area of ΔABC = `1/2 xx "AB" xx "AC"`
= `1/2 xx 5 xx 12`
= 30 cm2
Also, area of triangle = `1/2 xx "AD" xx "BC"`
30 = `1/2 xx "AD" xx 13`
`(30 xx 2)/13` = AD
AD = 4.6 cm
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle PQR with Q(3,2) and the mid-points of the sides through Q being (2,−1) and (1,2).
Find the area of the triangle formed by joining the mid-point of the sides of the triangle whose vertices are (0, –1), (2, 1) and (0, 3). Find the ratio of area of the triangle formed to the area of the given triangle.
If D, E and F are the mid-points of sides BC, CA and AB respectively of a ∆ABC, then using coordinate geometry prove that Area of ∆DEF = `\frac { 1 }{ 4 } "(Area of ∆ABC)"`
Find the equation of the line joining (1, 2) and (3, 6) using the determinants.
Find the missing value:
| Base | Height | Area of triangle |
| 15 cm | ______ | 87 cm2 |
Find the area of a triangle whose vertices are
`(at_1^2,2at_1),(at_2^2,2at_2)` and `(at_3^2,2at_3)`
Find the value of x for which the points (x, −1), (2, 1) and (4, 5) are collinear ?
Using integration, find the area of the triangle whose vertices are (2, 3), (3, 5) and (4, 4).
Find the area of the triangle whose vertices are (-2, 6), (3, -6), and (1, 5).
Find the area of the trapezium PQRS with height PQ given in the following figure.
