Advertisements
Advertisements
प्रश्न
ΔABC is right angled at A (see the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.

Advertisements
उत्तर
Area = `1/2 xx "Base" xx "Height"`
Area of ΔABC = `1/2 xx "AB" xx "AC"`
= `1/2 xx 5 xx 12`
= 30 cm2
Also, area of triangle = `1/2 xx "AD" xx "BC"`
30 = `1/2 xx "AD" xx 13`
`(30 xx 2)/13` = AD
AD = 4.6 cm
संबंधित प्रश्न
Find the values of k so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq. units.
Find the area of the following triangle:

If A(–5, 7), B(–4, –5), C(–1, –6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD
For what value of a the point (a, 1), (1, –1) and (11, 4) are collinear?
Find the area of ΔABC with A(1, –4) and midpoints of sides through A being (2, –1) and (0, –1).
If the points P(–3, 9), Q(a, b) and R(4, –5) are collinear and a + b = 1, find the values of a and b.
Find the value(s) of p for which the points (3p + 1, p), (p + 2, p – 5) and (p + 1, –p) are collinear ?
Find the area of the triangle whose vertices are (-2, 6), (3, -6), and (1, 5).
The points (1,1), (-2, 7) and (3, -3) are ______.
Find the missing value:
| Base | Height | Area of parallelogram |
| ______ | 15 cm | 154.5 cm2 |
