Advertisements
Advertisements
प्रश्न
Find the area of the following triangle:
Advertisements
उत्तर
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 5 cm,
Height = 3.2 cm
Area = `1/2 xx 5 xx 3.2`
= 8 cm2
APPEARS IN
संबंधित प्रश्न
Prove that the points (a, b + c), (b, c + a) and (c, a + b) are collinear
Find the area of the triangle whose vertices are: (2, 3), (-1, 0), (2, -4)
In each of the following find the value of 'k', for which the points are collinear.
(8, 1), (k, -4), (2, -5)
Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle
Find values of k if area of triangle is 4 sq. units and vertices are (k, 0), (4, 0), (0, 2).
Find the area of the following triangle:
Find the area of a triangle whose vertices are
(6,3), (-3,5) and (4,2)
Show that the points A(3, 1), B(0, –2), C(1, 1) and D(4, 4) are the vertices of a parallelogram ABCD.
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
If Δ = `|(1, x, x^2),(1, y, y^2),(1, z, z^2)|`, Δ1 = `|(1, 1, 1),(yz, zx, xy),(x, y, z)|`, then prove that ∆ + ∆1 = 0.
