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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the joint equation of the line passing through the origin and perpendicular to the lines x + 2y = 19 and 3x + y = 18

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प्रश्न

Find the joint equation of the line passing through the origin and perpendicular to the lines x + 2y = 19 and 3x + y = 18

बेरीज
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उत्तर

Let L1 and L2 be the lines passing through the origin and perpendicular to the lines x + 2y = 19 and 3x + y = 18 respectively.

Slopes of the lines x + 2y = 19 and 3x + y = 18 are `-1/2` and `- 3/1` = -3 respectively.

∴ slopes of the lines L1 and L2 are 2 and `1/3` respectively.

Since the lines L1 and L2 pass through the origin, their equations are

y = 2x  and y = `1/3`x

i.e. 2x - y = 0  and x - 3y = 0

∴ their combined equation is

(2x - y)(x - 3y) = 0

∴ 2x2 - 6xy - xy + 3y2 = 0

∴ 2x2 - 7xy + 3y2 = 0 

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पाठ 4: Pair of Straight Lines - Miscellaneous Exercise 4 [पृष्ठ १३१]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 1.11 | पृष्ठ १३१

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