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Evaluate: `Cos(Sin^-1 3/5+Sin^-1 5/13)` - Mathematics

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प्रश्न

Evaluate: `cos(sin^-1  3/5+sin^-1  5/13)`

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उत्तर

`cos(sin^-1  3/5+sin^-1  5/13)=cos{sin^-1(3/5sqrt(1-(5/13)^2)+5/13sqrt(1-(3/5)^2))}`

`=cos{sin^-1(3/5xx12/13+5/13xx4/5)}`

`=cos{sin^-1(36/65+4/13)}`

`=cos{sin^-1(56/65)}`

`=cos{cos^-1sqrt(1-(56/65)^2)}`          `[because sin^-1x=cos^-1sqrt(1-x^2)]`

`=cos{cos^-1  33/65}`

`=33/65`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.12 [पृष्ठ ८९]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.12 | Q 1 | पृष्ठ ८९

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