मराठी

Ed∫ex(1-x1+x2)2 dx is equal to ______.

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प्रश्न

`int "e"^x ((1 - x)/(1 + x^2))^2  "d"x` is equal to ______.

पर्याय

  • `"e"^x/(1 + x^2) + "C"`

  • `(-"e"^x)/(1 + x^2) + "C"`

  • `"e"^x/(1 + x^2)^2 + "C"`

  • `(-"e"^x)/(1 + x^2)^2 + "C"`

MCQ
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उत्तर

`int "e"^x ((1 - x)/(1 + x^2))^2  "d"x` is equal to `"e"^x/(1 + x^2) + "C"`.

Explanation:

Let I = `int "e"^x ((1 - x)/(1 + x^2))^2  "d"x`

= `int "e"^x [(1 + x^2 - 2x)/(1 + x^2)^2]"d"x`

= `int "e"^x [((1 + x^2))/(1 + x^2)^2 - (2x)/(1 + x^2)^2]"d"x`

= `int "e"^x [1/(1 + x^2) - (2x)/(1 + x^2)^2]"d"x`

Here f(x) = `1/(1 + x^2)`

∴ f'(x) = `(-2x)/(1 + x^2)^2`

Using `int "e"^x ["f"(x) + "f'"(x)]"d"x = "e"^x * "f"(x) + "C"`

∴ I = `"e"^x * 1/(1 + x^2) + "C" = "e"^x/(1 + x^2) + "C"`

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पाठ 7: Integrals - Exercise [पृष्ठ १६७]

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