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प्रश्न
Draw the intensity distribution as function of phase angle when diffraction of light takes place through coherently illuminated single slit.
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उत्तर
Intensity distribution as function of phase angle, when diffraction of light takes place through coherently illuminated single slit.
The Intensity pattern on the screen is shown in the given figure.

Width of central maximum = `(2"D"λ)/"a"`
APPEARS IN
संबंधित प्रश्न
Show that the angular width of the first diffraction fringe is half that of the central fringe.
If the source of light used in a Young's double slit experiment is changed from red to violet, ___________ .
In a Young’s double slit experiment, the path difference at a certain point on the screen between two interfering waves is `1/8`th of the wavelength. The ratio of intensity at this point to that at the centre of a bright fringe is close to ______.
ASSERTION (A): In an interference pattern observed in Young's double slit experiment, if the separation (d) between coherent sources as well as the distance (D) of the screen from the coherent sources both are reduced to 1/3rd, then new fringe width remains the same.
REASON (R): Fringe width is proportional to (d/D).
A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is ______.
What is fringe width?
What does \(x\) denote when deriving fringe positions?
What does \(\lambda\) denote in the fringe-position expressions?
What happens to fringe width when the wavelength of light increases while screen distance and slit separation remain unchanged?
What happens to fringe width when slit separation increases while wavelength and screen distance remain unchanged?
