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प्रश्न
Draw equipotential surfaces:
(1) in the case of a single point charge and
(2) in a constant electric field in Z-direction. Why are the equipotential surfaces about a single charge not equidistant?
(3) Can electric field exist tangential to an equipotential surface? Give reason
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उत्तर
(1)
(2)
The equipotential surfaces about a single charge are not equidistant because electric field due to a single change is not constant.
(3) If the electric field exist along tangential to an equipotential surface, a charged particle will experience a force along the tangential line and can move along it. As a charged particle can move only due to the potential difference (along with the direction of change of potential), this contradicts the concept of an equipotential surface.
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संबंधित प्रश्न
Draw a sketch of equipotential surfaces due to a single charge (-q), depicting the electric field lines due to the charge
Describe schematically the equipotential surfaces corresponding to
(a) a constant electric field in the z-direction,
(b) a field that uniformly increases in magnitude but remains in a constant (say, z) direction,
(c) a single positive charge at the origin, and
(d) a uniform grid consisting of long equally spaced parallel charged wires in a plane.
Depict the equipotential surface due to
(i) an electric dipole,
(ii) two identical positive charges separated by a distance.
- The potential at all the points on an equipotential surface is same.
- Equipotential surfaces never intersect each other.
- Work done in moving a charge from one point to other on an equipotential surface is zero.
Can two equipotential surfaces intersect each other?
A charge \[q_0\] is moved from point A to point B on the same equipotential surface. If the potentials at A and B are \[V_A\] and \[V_B\] respectively, the work done is:
If the electric field \[\vec{E}\] had a component along (tangent to) an equipotential surface, what contradiction would arise?
A point charge of \[1\ \mu\text{C}\] produces a potential \[V = \frac{kq}{r}\]. At what distance from the charge does the potential equal 90 V? (Take \[k = 9 \times 10^9\ \text{N m}^2/\text{C}^2\])
