मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Distance of point (−3, 4) from the origin is ______.

Advertisements
Advertisements

प्रश्न

Distance of point (−3, 4) from the origin is ______.

पर्याय

  • 7

  • 1

  • 5

  • 4

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

Distance of point (−3, 4) from the origin is 5.

Explanation:

Using the formula,

Distance = `sqrt(x^2 + y^2)`

= `sqrt((-3)^2 + 4^2)`

= `sqrt(9 + 16) = sqrt25 = 5`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2018-2019 (March) Balbharati Model Question Paper Set 3

संबंधित प्रश्‍न

Find the distance between the points:

A(–6, –4) and B(9, –12)


Find the distance between the points:

A(1, –3) and B(4, –6)


Find the distance between the following pair of points.

R(0, -3), S(0, `5/2`)


Find the distance between the following pair of point.

T(–3, 6), R(9, –10)


AB and AC are the two chords of a circle whose radius is r. If p and q are
the distance of chord AB and CD, from the centre respectively and if
AB = 2AC then proove that 4q2 = p2 + 3r2.


P and Q are two points lying on the x - axis and the y-axis respectively . Find the coordinates of P and Q if the difference between the abscissa of P and the ordinates of Q is 1 and PQ is 5 units.


Prove that the points (0,3) , (4,3) and `(2, 3+2sqrt 3)` are the vertices of an equilateral triangle.


Find the distance between the following pairs of points:
`(3/5,2) and (-(1)/(5),1(2)/(5))`


The distance between the points (3, 1) and (0, x) is 5. Find x.


Point P (2, -7) is the centre of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2, -4); calculate the length of AB.


Calculate the distance between A (5, -3) and B on the y-axis whose ordinate is 9.


Show that the points (a, a), (-a, -a) and `(-asqrt(3), asqrt(3))` are the vertices of an equilateral triangle.


Find distance between point A(7, 5) and B(2, 5).


If the distance between point L(x, 7) and point M(1, 15) is 10, then find the value of x.


Show that the point (11, –2) is equidistant from (4, –3) and (6, 3).


Show that the point (0, 9) is equidistant from the points (–4, 1) and (4, 1).


The distance between the points A(0, 6) and B(0, -2) is ______.


The distance of the point P(–6, 8) from the origin is ______.


A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.


Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×