मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Derive van’t Hoff general solution equation.

Advertisements
Advertisements

प्रश्न

Derive van’t Hoff general solution equation.

Derive van’t Hoff general solution equation for ‘n’ moles of solute. 

Derive van’t Hoff equation for dilute solutions.

व्युत्पत्ती
Advertisements

उत्तर १

According to van’t Hoff-Boyle’s law, osmotic pressure of a dilute solution is inversely proportional to the volume containing 1 mole of solute at constant temperature and according to van’t Hoff-Charles’ law, osmotic pressure of a dilute solution is directly proportional to the absolute temperature at constant concentration.

If π is the osmotic pressure, V is the volume of the solution and T is the absolute temperature, then

π ∝ `1/V`    ...(i) ...[van’t Hoff-Boyle’s law at constant temperature] 

∴ πV = constant

π ∝ T     .....(ii) ...[van’t Hoff-Charles’ law at constant concentration]

∴ `π/T` = constant

Combining (i) and (ii) we get,

π ∝ `T/V`

∴ π = Constant × `T/V`

∴ πV = R'T, where R' is a constant.

This equation is parallel to the ideal gas equation PV = RT (n = 1)
Since the calculated value of R' is almost same as R, the equation can be written as πV = RT (for 1 mole of solute )

This equation was derived for 1 mole of solute dissolved in V dm3. If n moles of solute are dissolved in V dmof solution, the equation becomes

πV = nRT

∴ `pi = (nRT)/V`

`C = n/V`

∴ π = CRT

where,

π = osmotic pressure,

C = concentration of solution in moles/litre

R = gas constant = 0.082 L atm mol−1 K1 or 8.314 J mol1 K1

T = absolute temperature

n = number of moles of solute,

V = volume of the solution.

shaalaa.com

उत्तर २

We have already seen that according to Boyle-van’t Hoff law

`pi prop 1/V` (at constant temperature)    ...(i)

and according to Charles’-van’t Hoff law

π ∝ T (at constant concentration)    ...(ii)

Combining Eqs. (i) and (ii), we have

`pi prop T/V`

or `pi = S T/V`

or πV = ST    ...(iii)

In this equation, S is a constant known as the solution constant. van’t Hoff showed that the value of solution constant (S) is equal to that of the gas constant, R, i.e.,

S = R

Hence, equation (iii) can be written as

πV = RT    ...(iv)

This equation is similar to the gas equation (PV = RT) and is known as the van’t Hoff equation.

For n moles of the solute dissolved in V litres of the solution, van’t Hoff equation can be written as

πV = nRT

shaalaa.com

Notes

Students can refer to the provided solutions based on their preferred marks.

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Solutions - SHORT ANSWER TYPE QUESTIONS [पृष्ठ १११]

APPEARS IN

नूतन Chemistry [English] Class 12 ISC
पाठ 1 Solutions
SHORT ANSWER TYPE QUESTIONS | Q 38. | पृष्ठ १११
नूतन Chemistry [English] Class 12 ISC
पाठ 1 Solutions
LONG ANSWER TYPE QUESTIONS | Q 21. ii. | पृष्ठ ११२

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The substance ‘X’, when dissolved in solvent water gave molar mass corresponding to the molecular formula ‘X3’. The van’t Hoff factor (i) is _______.

(A) 3

(B) 0.33

(C) 1.3

(D) 1


3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62 K. Calculate the van't Hoff factor and predict the nature of solute (associated or dissociated).

(Given : Molar mass of benzoic acid = 122 g mol−1, Kf for benzene = 4.9 K kg mol−1)


19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.0°C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.


Define the term abnormal molar mass.


How van’t Hoff factor is related to the degree of dissociation?


How will you convert the following in not more than two steps:

Benzoic acid to Benzaldehyde


Give reasons for the following

Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.


The Van't Hoff factor (i) for a dilute aqueous solution of the strong elecrolyte barium hydroxide is (NEET) ______.


The freezing point depression constant for water is 1.86° K Kg mol-1. If 5 g Na2SO4 is dissolved in 45 g water, the depression in freezing point is 3.64°C. The Vant Hoff factor for Na2SO4 is ______.


Phenol dimerizes in benzene having van’t Hoff factor 0.54. What is the degree of association?


The van’t Hoff factor (i) accounts for ____________.


We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van’t Hoff factor for these solutions will be in the order ______.


The values of Van’t Hoff factors for KCl, NaCl and K2SO4, respectively, are ______.


Van’t Hoff factor i is given by the expression:

(i)  i = `"Normal molar mass"/"Abnormal molar mass"`

(ii)  i = `"Abnormal molar mass"/"Normal molar mass"`

(iii) i = `"Observed colligative property"/"Calculated colligative property"`

(iv) i =  `"Calculated colligative property"/"Observed colligative property"`


Van't Hoff factor I is given by expression.


Maximum lowering of vapour pressure is observed in the case of ______.


Geraniol, a volatile organic compound, is a component of rose oil. The density of the vapour is 0.46 g L–1 at 257°C and 100 mm Hg. The molar mass of geraniol is ______ g mol–1. (Nearest Integer)

[Given: R = 0.082 L atm K–1 mol–1]


When 9.45 g of ClCH2COOH is added to 500 mL of water, its freezing point drops by 0.5°C. The dissociation constant of ClCH2COOH is x × 10−3. The value of x is ______. (Rounded-off to the nearest integer)

[\[\ce{K_{f(H_2O)}}\] = 1.86 K kg mol−1]


A storage battery contains a solution of H2SO4 38% by weight. At this concentration, Van't Hoff Factor is 2.50. At the battery content freeze temperature will be ______ K.

(Kf = 1.86 K Kg mol−1)


Consider the reaction

\[\begin{bmatrix}\begin{array}{cc}
\phantom{.......}\ce{CH3}\\
\phantom{....}|\\
\ce{CH3CH2CH2 - \overset{⊕}{N} - CH2CH3}\\
\phantom{....}|\\
\phantom{.......}\ce{CH3}
\end{array}\end{bmatrix}\]\[\ce{OH^- ->[Heat] ?}\]

Which of the following is formed in a major amount?


A molecule M associates in a given solvent according to the equation \[\ce{M <=> (M)_n}\]. For a certain concentration of M, the van't Hoff factor was found to be 0.9 and the fraction of associated molecules was 0.2. The value of n is ______.


When 19.5 g of F – CH2 – COOH (Molar mass = 78 g mol−1), is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C. Calculate the degree of dissociation of F – CH2 – COOH.

[Given: Kf for water = 1.86 K kg mol−1]


Calculate Van't Hoff factor for an aqueous solution of K3 [Fe(CN)6] if the degree of dissociation (α) is 0.852. What will be boiling point of this solution if its concentration is 1 molal? (Kb = 0.52 K kg/mol)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×