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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Van’t Hoff factor i is given by the expression: (i) i = Normal molar massAbnormal molar massNormal molar massAbnormal molar mass (ii) i = Abnormal molar massNormal molar massAbnormal mola

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प्रश्न

Van’t Hoff factor i is given by the expression:

(i)  i = `"Normal molar mass"/"Abnormal molar mass"`

(ii)  i = `"Abnormal molar mass"/"Normal molar mass"`

(iii) i = `"Observed colligative property"/"Calculated colligative property"`

(iv) i =  `"Calculated colligative property"/"Observed colligative property"`

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उत्तर

(i)  i = `"Normal molar mass"/"Abnormal molar mass"`

(iii) i = `"Observed colligative property"/"Calculated colligative property"`

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पाठ 2: Solutions - Exercises [पृष्ठ २३]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 2 Solutions
Exercises | Q II. 30. | पृष्ठ २३

संबंधित प्रश्‍न

Derive van’t Hoff general solution equation.


Define van’t Hoff factor.


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Define the term abnormal molar mass.


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Benzoic acid to Benzaldehyde


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What is the expected each water van't Hoff factor for and K4[F4(CN6)] when it completely dissociated in waters.


Maximum lowering of vapour pressure is observed in the case of ______.


When 9.45 g of ClCH2COOH is added to 500 mL of water, its freezing point drops by 0.5°C. The dissociation constant of ClCH2COOH is x × 10−3. The value of x is ______. (Rounded-off to the nearest integer)

[\[\ce{K_{f(H_2O)}}\] = 1.86 K kg mol−1]


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A molecule M associates in a given solvent according to the equation \[\ce{M <=> (M)_n}\]. For a certain concentration of M, the van't Hoff factor was found to be 0.9 and the fraction of associated molecules was 0.2. The value of n is ______.


When 19.5 g of F – CH2 – COOH (Molar mass = 78 g mol−1), is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C. Calculate the degree of dissociation of F – CH2 – COOH.

[Given: Kf for water = 1.86 K kg mol−1]


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Calculate Van't Hoff factor for an aqueous solution of K3 [Fe(CN)6] if the degree of dissociation (α) is 0.852. What will be boiling point of this solution if its concentration is 1 molal? (Kb = 0.52 K kg/mol)


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