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प्रश्न
Derive Meyer’s relation for an ideal gas.
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उत्तर
Meyer’s relation: Consider p mole of an ideal gas in a container with volume V, pressure P and temperature T.
When the gas is heated at constant volume the temperature increases by dT. As no work is done by the gas, the heat that flows into the system will increase only the internal energy. Let the change in internal energy be dU.
If Cv is the molar specific heat capacity at constant volume, from the equation.
`"C"_"v" = 1/µ "dU"/"dT"` ..........(1)
dU = µCvdT .........(2)
Suppose the gas is heated at constant pressure so that the temperature increases by dT. If ‘Q’ is the heat supplied in this process and ‘dV’ the change in volume of the gas.
Q = µCPdT …............(3)
If W is the work done by the gas in this process, then
W = PdV …................(4)
But from the first law of thermodynamics,
Q = dU + W …...............(5)
Substituting equations (2), (3) and (4) in (5), we get,
µCpdT = µCvdT + PdV
For mole of an ideal gas, the equation of state is given by
PV = µRT ⇒ PdV + VdP = µRdT
Since the pressure is constant, dP = 0
∴ CpdT = CvdT + RdT
∴ CP = Cv +R (or) Cp − Cv = R ......(6)
This relation is called Meyer’s relation It implies that the molar specific heat capacity of an ideal gas at constant pressure is greater than molar specific heat capacity at constant volume. The relation shows that specific heat at constant pressure (sp) is always greater than specific heat at constant volume (sv).
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| Gas |
Molar specific heat (Cv) (cal mol–1 K–1) |
| Hydrogen | 4.87 |
| Nitrogen | 4.97 |
| Oxygen | 5.02 |
| Nitric oxide | 4.99 |
| Carbon monoxide | 5.01 |
| Chlorine | 6.17 |
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