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Consider a Wire of Length 4 M and Cross-sectional Area 1 Mm2 Carrying a Current of 2 A. If Each Cubic Metre of the Material Contains 1029 Free Electrons - Physics

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प्रश्न

Consider a wire of length 4 m and cross-sectional area 1 mm2 carrying a  current of 2 A. If each cubic metre of the material contains 1029 free electrons, find the average time taken by an electron to cross the length of the wire.

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उत्तर

Given:-

Current through the wire, i = 2 A

Length of the wire, l = 4 m

Area of cross section, A = 1 mm2 = 1 × 10–6 m2

Number of electrons per unit volume, n = 1029

We know:-

\[i = nA V_d e\]

\[ \Rightarrow  V_d  = \frac{i}{nAe}\]

\[ = \frac{2}{{10}^{29} \times {10}^{- 6} \times 1 . 6 \times {10}^{- 19}}\]

\[ \Rightarrow  V_d  = \frac{1}{8000}  m/s,\]

where Vd is the drift speed.

Let t be the time taken by an electron to cross the length of the wire.

\[\Rightarrow t = \frac{\text{Length of the wire}}{\text{Drift speed}}\] 

\[ = \frac{l}{V_d}\] 

\[ \therefore   t = \frac{4}{\frac{1}{8000}}\] 

\[ = 32 \times  {10}^3   s\]

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पाठ 10: Electric Current in Conductors - Exercises [पृष्ठ १९८]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 10 Electric Current in Conductors
Exercises | Q 8 | पृष्ठ १९८

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