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प्रश्न
Compute the heat generated while transferring 96000 coulombs of charge in two hours through a potential difference of 40 V.
संख्यात्मक
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उत्तर
Given:
Charge (Q) = 96000 C,
Time (t) = 2h,
Potential difference (V) = 40V
The heat generated,
H = VIt
= `"V" xx "Q"/"t" xx "t"`
= V × Q
= 40 × 96000
= 3840000 J
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2019-2020 (March) Delhi Set 3
