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Calculate the resultant capacitances for each of the following combinations of capacitors.

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प्रश्न

Calculate the resultant capacitances for each of the following combinations of capacitors.






दीर्घउत्तर
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उत्तर



  1. Parallel combination of capacitor 1 and 2
    Cp = C0 + C0 = 2C0
    Series combination of capacitor Cp and 3
    `1/"C"_"s" = 1/"C"_"p" + 1/"C"_3 = 1/(2 "C"_0) + 1/"C"_0 = ("or") 1/"C"_"s" = 3/2 "C"_0 ("or") "C"_"s" = 2/3 "C"_0`


  2. `1/"C"_("s"_1) = 1/"C"_1 + 1/"C"_2 = 1/"C"_0 + 1/"C"_0 = 1/"C"_0` (or)
    `1/"C"_("s"_1) = 2/"C"_0 ("or")  "C"_("S"_1) = "C"_0/2`
    Similarly 3 and 4 are series combination
    `1/"C"_("s"_1) = 1/"C"_3 + 1/"C"_4 = 1/"C"_0 + 1/"C"_0 = 2/"C"_0  ("or") "C"_("S"_2) = "C"_0/2`
    `"C"_("S"_1) and "C"_("S"_2)` are in parallel combination
    `"C"_"p" = "C"_("S"_1) + "C"_("S"_2) = "C"_0/2 + "C"_0/2 ("or") "C"_"p" = (2"C"_0)/2 "C"_"p" = "C"_0`
  3. Capacitor 1, 2 and 3 are in parallel combination
    Cp = C0 + C0 + C0 = 3C0
    Cp = 3C0
  4. Capacitar C1 and C2 are in combination
    `1/"C"_("s"_1) = ("C"_1 + "C"_2)/("C"_1"C"_2)`
    `"C"_("s"_1) = ("C"_1"C"_2)/("C"_1 + "C"_2)`
    Similarly C3 and C4 are in series combination

    `1/"C"_("s"_2) = 1/"C"_3 + 1/"C"_4 = ("C"_3 + "C"_4)/("C"_3"C"_4)`
    `"C"_("s"_2) = ("C"_3"C"_4)/("C"_3 + "C"_4)`
    `"C"_("s"_1) and "C"_("s"_2)` are in parallel combination across RS:
    CP = `"C"_("S"_1) + "C"_("S"_2)`

    `= ("C"_1"C"_2)/("C"_1 + "C"_2) + ("C"_3"C"_4)/("C"_3 + "C"_4)`

    `= ("C"_1"C"_2 ("C"_3 + "C"_4) + "C"_3"C"_4("C"_1 + "C"_2))/(("C"_1 + "C"_2)("C"_3 + "C"_4))`

    `"C"_"P" = ("C"_1"C"_2"C"_3 + "C"_1"C"_2"C"_4 + "C"_3"C"_4"C"_1 + "C"_3"C"_4"C"_2)/(("C"_1 + "C"_2)("C"_3 + "C"_4))`
  5. Capacitor 1 and 2 are series combination
    `1/"C"_("s"_1) = 1/"C"_1 + 1/"C"_2 = 1/"C"_0 + 1/"C"_0 = 1/"C"_0`
    `1/"C"_("s"_1) = 2/"C"_0` (or) `"C"_"s"_1 = "C"_0/2`

    Similarly 3 and 4 are series combination
    `1/"C"_("s"_1) = 2/"C"_0  ("or") "C"_("s"_2) = "C"_0/2`
    Three capacitors are in parallel combination
    `"C"_"P" = "C"_0/2 + "C"_0 + "C"_0/2 + (2"C"_0)/2 + "C"_0/2 = (4"C"_0)/2`
    `"C"_"P" = 2 "C"_0`
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पाठ 1: Electrostatics - Evaluation [पृष्ठ ७७]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 1 Electrostatics
Evaluation | Q 11. | पृष्ठ ७७

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