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प्रश्न
Calculate activation energy for a reaction of which rate constant becomes four times when temperature changes from 30 °C to 50 °C. (Given R = 8.314 JK−1 mol−1).
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उत्तर
Calculation of activation energy:
Given: T1 = 30° C = 303 K, T2 = 50° C = 323 K
Rate constant becomes four times when temperature changes from 30° C to 50° C.
∴ k2 = 4k1
or `k_2/k_1 = 4`
To find: Activation energy (Ea)
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