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Block A of weight 100 N rests on a frictionless inclined plane of slope angle 30° (figure). A flexible cord attached to A passes over a frictonless pulley and is connected to block B of weight W.

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प्रश्न

Block A of weight 100 N rests on a frictionless inclined plane of slope angle 30° (figure). A flexible cord attached to A passes over a frictonless pulley and is connected to block B of weight W. Find the weight W for which the system is in equilibrium.

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उत्तर

In equilibrium, the force mg sin θ acting on block A parallel to the plane should be balanced by the tension in the string, ie.,

mg sin θ = T = F    [∵ T = F given]  ......(i)

And for block B, w = T = F   ......(ii)

Where w is the weight of block B.

From equations (i) and (ii), we get,

w = mg sin θ

= 100 × sin 30°  .....[∵ mg = 100 N]

= `100 xx 1/2` N 

= 50 N

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पाठ 5: Laws of Motion - Exercises [पृष्ठ ३५]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
पाठ 5 Laws of Motion
Exercises | Q 5.29 | पृष्ठ ३५

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