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प्रश्न
- Assertion (A): Propagation of light through an optical fibre is due to total internal reflection taking place at the core-cladding interface.
- Reason (R): Refractive index of the material of the cladding of the optical fibre is greater than that of the core.
पर्याय
If both Assertion and Reason are true and Reason is the correct explanation of Assertion.
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
If Assertion is true but Reason is false.
If both Assertion and Reason are false.
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उत्तर
If Assertion is true but Reason is false.
Explanation:
Propagation of light through an optical fibre is due to total internal reflection taking place at the core-cladding interface. The claim is correct.
One requirement for total internal reflection is that light goes from a denser to a rarer medium. Total internal reflection occurs in optical fibre as light passes from the core to the cladding. As a result, the core's refractive index should be larger than that of the cladding. As a result, the reason is untrue.
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संबंधित प्रश्न
A ray of light travels from water to air as shown in the diagram given below :

1) Copy the diagram and complete the path of the way. Given the critical angle for water is 48°.
2) State the condition so that internal reflection occurs in the above diagram.
The figure shows a ray of light falling normally on the face AB of an equilateral glass prism having refractive index`3/2`, placed in water of refractive index `4/3`.Will this ray suffer total internal reflection on striking the face AC? Justify your answer.

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Define critical angle for a given medium.
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Express the refractive index μ of a medium in terms of the angle of incidence i in air and the angle of refraction r in a denser medium.
Optical Fibres are based on the phenomenon of dispersion.
A rectangular block of glass ABCD has a refractive index 1.6. A pin is placed midway on the face AB (Figure). When observed from the face AD, the pin shall ______.

- appear to be near A.
- appear to be near D.
- appear to be at the centre of AD.
- not be seen at all.
A ray of light passes from vacuum into a medium of refractive index µ, the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is ______.
