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प्रश्न
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5NHCH3, C6H5CH2NH2
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उत्तर
C6H5NHCH3 is more basic than C6H5NH2 due to the presence of an electron-donating −CH3 group in C6H5NHCH3.
Again, in C6H5NHCH3, −C6H5 group is directly attached to the N-atom. However, it is not so in C6H5CH2NH2. Thus, in C6H5NHCH3, the −R effect of −C6H5 group decreases the electron density over the N-atom. Therefore, C6H5CH2NH2 is more basic than C6H5NHCH3.
Hence, the increasing order of the basic strengths of the given compounds is as follows:
C6H5NH2 < C6H5NHCH3 < C6H5CH2NH2
संबंधित प्रश्न
Write the structures of main products when aniline reacts with the following reagents : HCl
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In decreasing order of the pKb values:
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In increasing order of basic strength:
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Write the structures of the main products of the following reactions:

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C6H5NH2, C2H5NH2, (C2H5)2NH2, NH3
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\[\ce{H2O, NH3, OH-, NH^{-}2}\]
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Arrange the decreasing order of pKb values.
\[\ce{C6H5NH2, C6H5NHCH3, C6H5CH2NH2, CH3NH2, NH3}\]
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