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प्रश्न
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5NHCH3, C6H5CH2NH2
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उत्तर
C6H5NHCH3 is more basic than C6H5NH2 due to the presence of an electron-donating −CH3 group in C6H5NHCH3.
Again, in C6H5NHCH3, −C6H5 group is directly attached to the N-atom. However, it is not so in C6H5CH2NH2. Thus, in C6H5NHCH3, the −R effect of −C6H5 group decreases the electron density over the N-atom. Therefore, C6H5CH2NH2 is more basic than C6H5NHCH3.
Hence, the increasing order of the basic strengths of the given compounds is as follows:
C6H5NH2 < C6H5NHCH3 < C6H5CH2NH2
संबंधित प्रश्न
Write the chemical equations involved when aniline is treated with the following reagents: HCI
Write a short note on the following:
Carbylamine reaction
Write the structures of the main products of the following reactions:

Write the structures of the main products of the following reactions:

The following reaction takes place in the presence of:

The correct decreasing order of basic strength of the following species is ______.
\[\ce{H2O, NH3, OH-, NH^{-}2}\]
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Account for the following:
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When methyl iodide is heated with ammonia, what is the product obtained?
A Solution of methyl amine shows which type of property with litmus paper?
Which of the following is most basic?
By the presence of a halogen atom in the ring, what is the effect of this on basic property of aniline?
What is the correct decreasing order of the basic character of the three amines and ammonia?
Give reasons for the following observation:
pKb of aniline is lower than the m-nitroaniline.
Among the following, which has the highest value of pKb?
State one reason for the following:
Alkylamine is soluble in water, whereas arylamine is insoluble in water.
The correct order of the increasing basic nature of Ammonia, Methylamine and Aniline is:
