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प्रश्न
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5NHCH3, C6H5CH2NH2
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उत्तर
C6H5NHCH3 is more basic than C6H5NH2 due to the presence of an electron-donating −CH3 group in C6H5NHCH3.
Again, in C6H5NHCH3, −C6H5 group is directly attached to the N-atom. However, it is not so in C6H5CH2NH2. Thus, in C6H5NHCH3, the −R effect of −C6H5 group decreases the electron density over the N-atom. Therefore, C6H5CH2NH2 is more basic than C6H5NHCH3.
Hence, the increasing order of the basic strengths of the given compounds is as follows:
C6H5NH2 < C6H5NHCH3 < C6H5CH2NH2
संबंधित प्रश्न
Arrange the following in increasing order of their basic strength in aqueous solution:
\[\ce{CH3NH2, (CH3)3N, (CH3)2NH}\]
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Aniline, p-nitroaniline, p-methylaniline - in the increasing order of their basic strength
Write the chemical equations involved when aniline is treated with the following reagents: HCI
Arrange the following:
In decreasing order of the pKb values:
C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2
Arrange the following:
In increasing order of basic strength:
Aniline, p-nitroaniline and p-toluidine
Arrange the following:
In decreasing order of basic strength in the gas phase:
C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3
Write the structures of the main products of the following reactions:

When methyl iodide is heated with ammonia, what is the product obtained?
A Solution of methyl amine shows which type of property with litmus paper?
Which of the following statement is true about methyl amine?
Which of the following compound cannot be produced if 1-propane amine is treated with NaNO2 and HCl?
Among the following, which has the highest value of pKb?
The correct order of the increasing basic nature of Ammonia, Methylamine and Aniline is:
