Advertisements
Advertisements
प्रश्न
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2
Advertisements
उत्तर
C6H5N(CH3)2 is more basic than C6H5NH2 due to the presence of the +I effect of two −CH3 groups in C6H5N(CH3)2. Further, CH3NH2 contains one −CH3 group while (C2H5)2NH contains two −C2H5 groups. Thus, (C2H5)2NH is more basic than C2H5NH2.
Now, C6H5N(CH3)2 is less basic than CH3NH2 because of the −R effect of −C6H5 group.
Hence, the increasing order of the basic strengths of the given compounds is as follows:
C6H5NH2 < C6H5N(CH3)2 < CH3NH2 < (C2H5)2NH
APPEARS IN
संबंधित प्रश्न
Arrange the following:
Aniline, p-nitroaniline, p-methylaniline - in the increasing order of their basic strength
Write the structures of main products when aniline reacts with the following reagents : HCl
Write the chemical equations involved when aniline is treated with the following reagents: HCI
Why does NH3 act as a Lewis base?
Arrange the following:
In increasing order of basic strength:
Aniline, p-nitroaniline and p-toluidine
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5NHCH3, C6H5CH2NH2
Write a short note on the following:
Carbylamine reaction
Write the structures of the main products of the following reactions:

Write the structures of the main products of the following reactions:

The following reaction takes place in the presence of:

Arrange the following in decreasing order of their basic strength:
C6H5NH2, C2H5NH2, (C2H5)2NH2, NH3
The correct decreasing order of basic strength of the following species is ______.
\[\ce{H2O, NH3, OH-, NH^{-}2}\]
Account for the following:
Acylation of aniline is carried out in the presence of pyridine.
When ethanol is mixed with ammonia and passed over alumina the compound formed is which compound?
Which of the following statement is true about methyl amine?
Which of the following is most basic?
Give reasons for the following observation:
pKb of aniline is lower than the m-nitroaniline.
