Advertisements
Advertisements
प्रश्न
Arrange the following:
In increasing order of basic strength:
Aniline, p-nitroaniline and p-toluidine
Advertisements
उत्तर

In p-toluidine, the presence of an electron-donating −CH3 group increases the electron density on the N-atom. Thus, p-toluidine is more basic than aniline.
On the other hand, the presence of electron-withdrawing −NO2 group decreases the electron density over the N-atom in p-nitroaniline. Thus, p-nitroaniline is less basic than aniline.
Hence, the increasing order of the basic strengths of the given compounds is as follows:
p-Nitroaniline < Aniline < p-Toluidine
APPEARS IN
संबंधित प्रश्न
Arrange the following in increasing order of their basic strength in aqueous solution:
\[\ce{CH3NH2, (CH3)3N, (CH3)2NH}\]
Arrange the following:
Aniline, p-nitroaniline, p-methylaniline - in the increasing order of their basic strength
Write the chemical equations involved when aniline is treated with the following reagents: HCI
Why does NH3 act as a Lewis base?
Arrange the following:
In decreasing order of the pKb values:
C2H5NH2, C6H5NHCH3, (C2H5)2NH and C6H5NH2
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2
Arrange the following:
In increasing order of basic strength:
C6H5NH2, C6H5NHCH3, C6H5CH2NH2
Arrange the following:
In decreasing order of basic strength in the gas phase:
C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3
Write the structures of the main products of the following reactions:

Write the structures of the main products of the following reactions:

The correct decreasing order of basic strength of the following species is ______.
\[\ce{H2O, NH3, OH-, NH^{-}2}\]
Explain why \[\ce{MeNH2}\] is stronger base than \[\ce{MeOH}\]?
When methyl iodide is heated with ammonia, what is the product obtained?
Give reasons for the following observation:
pKb of aniline is lower than the m-nitroaniline.
Account for the following:
Arrange the following compounds in the increasing order of their basic strength in aqueous solution: CH3NH2,(CH3)3N,(CH3)2NH
Which of the following compound cannot be produced if 1-propane amine is treated with NaNO2 and HCl?
Among the following, which has the highest value of pKb?
Arrange the decreasing order of pKb values.
\[\ce{C6H5NH2, C6H5NHCH3, C6H5CH2NH2, CH3NH2, NH3}\]
