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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Answer the following question. Discuss the following as special cases of elastic collisions and obtain their exact or approximate final velocities in terms of their initial velocities.

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प्रश्न

Answer the following question.

Discuss the following as special cases of elastic collisions and obtain their exact or approximate final velocities in terms of their initial velocities.

  1. Colliding bodies are identical.
  2. A very heavy object collides on a lighter object, initially at rest.
  3. A very light object collides on a comparatively much massive object, initially at rest.
थोडक्यात उत्तर
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उत्तर

The final velocities after a head-on elastic collision is given as,

`"v"_1 = "u"_1 [("m"_1 - "m"_2)/("m"_1 + "m"_2)] + "u"_2["2m"_2/("m"_1 + "m"_2)]`

`"v"_1 = "u"_1["2m"_1/("m"_1 + "m"_2)] + "u"_2[("m"_2 - "m"_1)/("m"_1 + "m"_2)]`

  1. Colliding bodies are identical
    If m1 = m2, then v1 = u2 and v2 = u1. Thus, objects will exchange their velocities after head on elastic collision.
  2. A very heavy object collides with a lighter object, initially at rest.
    Let m1 be the mass of the heavier body and m2 be the mass of the lighter body i.e., m1 >> m2; the lighter particle is at rest i.e., u2 = 0 then,
    m1 ± m2 ≅ m1 and `"m"_2/("m"_1 + "m"_2) ~= 0,`
    ∴ v1 ≅ u1 and v2 ≅ 2u1
    i.e., the heavier colliding body is left unaffected and the lighter body which is struck travels with double the speed of the massive striking body.
  3. A very light object collides on a comparatively much massive object, initially at rest.
    If m1 is the mass of a light body and m2 is the mass of a heavy body i.e., m1 << m2 and u2 = 0. Thus, m1 can be neglected.
    Hence v1 ≅ - uand v2 ≅ 0.
    i.e., the tiny (lighter) object rebounds with the same speed while the massive object is unaffected.
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पाठ 4: Laws of Motion - Exercises [पृष्ठ ७५]

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बालभारती Physics [English] Standard 11 Maharashtra State Board
पाठ 4 Laws of Motion
Exercises | Q 2. (xv) | पृष्ठ ७५

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