मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

A Trolley of Mass 200 Kg Moves with a Uniform Speed of 36 Km/H on a Frictionless Track. a Child of Mass 20 Kg Runs on the Trolley from One End to the Other (10 M Away) with a Speed of 4 M S–1 Relative to the Trolley in a Direction Opposite to the Its Motion, and Jumps Out of the Trolley. What is the Final Speed of the Trolley? How Much Has the Trolley Moved from the Time the Child Begins to Run

Advertisements
Advertisements

प्रश्न

A trolley of mass 200 kg moves with a uniform speed of 36 km/h on a frictionless track. A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a speed of 4 m s–1 relative to the trolley in a direction opposite to the its motion, and jumps out of the trolley. What is the final speed of the trolley? How much has the trolley moved from the time the child begins to run?

Advertisements

उत्तर १

Mass of the trolley, M = 200 kg

Speed of the trolley, v = 36 km/h = 10 m/s

Mass of the boy, m = 20 kg

Initial momentum of the system of the boy and the trolley

= (M + m)v 

= (200 + 20) × 10

= 2200 kg m/s

Let v' be the final velocity of the trolley with respect to the ground.

Final velocity of the boy with respect to the ground = v' - 4

Final momentum = Mv' + m(v' - 4)

= 200v' + 20v' - 80

= 220v' – 80

As per the law of conservation of momentum: 

Initial momentum = Final momentum

2200 = 220v' – 80

∴ v' = 2280 / 220 = 10.36 m/s

Length of the trolley, l = 10 m

Speed of the boy, v'' = 4 m/s

Time taken by the boy to run, t = 10/4 = 2.5 s

∴ Distance moved by the trolley = v'' × t= 10.36 × 2.5 = 25.9 m

shaalaa.com

उत्तर २

Let there be an observer travelling parallel to the trolley with the same speed. He will observe the initial momentum of the trolley of mass M and child of mass m as zero. When the child jumps in opposite direction, he will observe the increase in the velocity of the trolley by Δv.

Let u be the velocity of the child. He will observe child landing at velocity (u – Δu) Therefore, initial momentum = 0

Final momentum = MΔ v – m (u – Δv)

Hence, MΔ v – m (u – Δv) = 0

Whence Δv =mu/ M + m

Putting values Δv =4 x 20/ 20 + 220 = ms-1

∴ Final speed of trolley is 10.36 ms-1.

The child take 2.5 s to run on the trolley.

Therefore, the trolley moves a distance = 2.5 x 10.36 m = 25.9 m.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

State if the following statement is true or false. Give a reason for your answer.

In an elastic collision of two bodies, the momentum and energy of each body is conserved.


State if the following statement is true or false. Give a reason for your answer. 

Total energy of a system is always conserved, no matter what internal and external forces on the body are present.


Answer carefully, with reason:

In an inelastic collision of two billiard balls, is the total kinetic energy conserved during the short time of collision of the balls (i.e., when they are in contact)?


Answer carefully, with reason:

If the potential energy of two billiard balls depends only on the separation distance between their centres, is the collision elastic or inelastic? (Note, we are talking here of potential energy corresponding to the force during collision, not gravitational potential energy.)


A molecule in a gas container hits a horizontal wall with speed 200 m s–1 and angle 30° with the normal, and rebounds with the same speed. Is momentum conserved in the collision? Is the collision elastic or inelastic?


Define the following:

Coefficient of restitution


Two different unknown masses A and B collide. A is initially at rest when B has a speed v. After collision B has a speed v/2 and moves at right angles to its original direction of motion. Find the direction in which A moves after the collision.


A ball moving with velocity 5 m/s collides head on with another stationary ball of double mass. If the coefficient of restitution is 0.8, then their velocities (in m/s) after collision will be ____________.


In Rutherford experiment, for head-on collision of a-particles with a gold nucleus, the impact parameter is ______.


A body of mas 'm' moving with speed 3 m/s collides with a body of mass '2m' at rest. The coalesced mass will start to move with a speed of ______.


Two identical ball bearings in contact with each other and resting on a frictionless table are hit head-on by another ball bearing of the same mass moving initially with a speed V as shown in figure.

If the collision is elastic, which of the following (Figure) is a possible result after collision?


A ball of mass m, moving with a speed 2v0, collides inelastically (e > 0) with an identical ball at rest. Show that for head-on collision, both the balls move forward.


Consider a one-dimensional motion of a particle with total energy E. There are four regions A, B, C and D in which the relation between potential energy V, kinetic energy (K) and total energy E is as given below:

Region A : V > E
Region B : V < E
Region C : K > E
Region D : V > K

State with reason in each case whether a particle can be found in the given region or not.


A rod of mass M and length L is lying on a horizontal frictionless surface. A particle of mass 'm' travelling along the surface hits at one end of the rod with velocity 'u' in a direction perpendicular to the rod. The collision is completely elastic. After collision, particle comes to rest. The ratio of masses `(m/M)` is `1/x`. The value of 'x' will be ______.


A particle of mass m with an initial velocity u`hat"i"` collides perfectly elastically with a mass 3m at rest. It moves with a velocity v`hat"j"` after collision, then, v is given by :


A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 ms-1 gets embedded in it, then loss of kinetic energy will be ______.


The dimension of mutual inductance is ______.


Before collision, what is the position of objects?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×