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A ball of mass m, moving with a speed 2v0, collides inelastically (e > 0) with an identical ball at rest. Show that for head-on collision, both the balls move forward.

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प्रश्न

A ball of mass m, moving with a speed 2v0, collides inelastically (e > 0) with an identical ball at rest. Show that for head-on collision, both the balls move forward.

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उत्तर

Let v1 and v2 be the velocities of the two balls after a collision.

Now, by the principle of conservation of linear momentum,

2mv0 = mv1 + mv2

or 2v0 = v1 + v2

And e = `(v_2 - v_1)/(2v_0)`

⇒ v2 = v1 + 2v0e

∴ 2v1 = 2v0 – 2ev0

∴ v1 = v0 (1 – e)

Since, e < 1 ⇒ v1 has the same sign as v0, therefore, the ball moves on after collision.

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पाठ 6: Work, Energy and Power - Exercises [पृष्ठ ४६]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
पाठ 6 Work, Energy and Power
Exercises | Q 6.35 (a) | पृष्ठ ४६

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