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प्रश्न
Answer the following in brief.
Give one example and explain why it is pseudo-first-order.
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उत्तर
Example: Consider the hydrolysis of methyl acetate.
\[\ce{CH3COOCH3_{(aq)} + H2O_{(l)} -> CH3COOH_{(aq)} + CH3OH_{(aq)}}\]
The rate law is rate = k' [CH3COOCH3][H2O]
Explanation: The reaction was expected to follow the second-order kinetics, however, obeys the first order. The reason is that solvent water is present in such large excess that the change in its concentration is negligible compared to the initial one or its concentration remains constant. Thus [H2O] = constant = k''. The rate law becomes rate = k' [CH3COOCH3]k'' = k [CH3COOCH3]
where, k = k'k''
The reaction is thus of first order.
संबंधित प्रश्न
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| t (min) | 0 | 10 | 20 |
| V (ml) | 46.1 | 29.8 | 19.3 |
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