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प्रश्न
Angle A of an isosceles trapezium ABCD is 115°; find the angles B, C and D.
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उत्तर
Since the base angles of an isosceles trapezium are equal,
∴ ∠A = ∠B = 115°
Also, ∠A and ∠D are co-interior angles and their sum = 180°
∴ ∠A + ∠D = 180°
⇒115° + ∠D = 180°
⇒ ∠D = 180° - 115°
⇒ ∠D = 65°
Also, ∠D = ∠C = 65°
∴ ∠B = 115°, ∠C = 65°, ∠D = 65°
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