Advertisements
Advertisements
प्रश्न
Angle A of an isosceles trapezium ABCD is 115°; find the angles B, C and D.
Advertisements
उत्तर
Since the base angles of an isosceles trapezium are equal,
∴ ∠A = ∠B = 115°
Also, ∠A and ∠D are co-interior angles and their sum = 180°
∴ ∠A + ∠D = 180°
⇒115° + ∠D = 180°
⇒ ∠D = 180° - 115°
⇒ ∠D = 65°
Also, ∠D = ∠C = 65°
∴ ∠B = 115°, ∠C = 65°, ∠D = 65°
APPEARS IN
संबंधित प्रश्न
Given here are some figures:
 |
 |
 |
 |
 |
 |
 |
 |
Classify each of them on the basis of the following:
- Simple curve
- Simple closed curve
- Polygon
- Convex polygon
- Concave polygon
In a quadrilateral, define of the following Vertices .
Three angles of a quadrilateral are equal. Fourth angle is of measure 150°. What is the measure of equal angles.
Observe the figure below and find out their name.
One angle of a hexagon is 140° and the remaining angles are in the ratio 4 : 3 : 4 : 5 : 4. Calculate the measures of the smallest and the largest angles.
In a quadrilateral ABCD, ∠A = 72° and ∠C is the supplementary of ∠A. The other two angles are 2x – 10 and x + 4. Find the value of x and the measure of all the angles
In the quadrilateral ABCD, AB = BC and AD = DC Measure of ∠BCD is
If one angle of a cyclic quadrilateral is 75°, then the opposite angle is
Both the pairs of opposite angles of a quadrilateral are equal and supplementary. Find the measure of each angle.
In the following figure, What is BD – BE?
