Advertisements
Advertisements
प्रश्न
Angle A of an isosceles trapezium ABCD is 115°; find the angles B, C and D.
Advertisements
उत्तर
Since the base angles of an isosceles trapezium are equal,
∴ ∠A = ∠B = 115°
Also, ∠A and ∠D are co-interior angles and their sum = 180°
∴ ∠A + ∠D = 180°
⇒115° + ∠D = 180°
⇒ ∠D = 180° - 115°
⇒ ∠D = 65°
Also, ∠D = ∠C = 65°
∴ ∠B = 115°, ∠C = 65°, ∠D = 65°
APPEARS IN
संबंधित प्रश्न
In Fig. 16.19, ABCD is a quadrilateral.
How many pairs of adjacent sides are there?
Use the following figure to find the value of x
The angles A, B, C and D of a quadrilateral are in the ratio 2 : 3 : 2 : 3. Show this quadrilateral is a parallelogram.
One angle of a hexagon is 140° and the remaining angles are in the ratio 4 : 3 : 4 : 5 : 4. Calculate the measures of the smallest and the largest angles.
One angle of a pentagon is 160° and the rest are all equal angles. Find the measure of the equal angles.
In quadrilateral HOPE, the pairs of opposite sides are ______.
If the sum of two angles is greater than 180°, then which of the following is not possible for the two angles?
In the following figure,
∠COA is a/an ______ angle
Using the information given, name the right angles in part of figure:
AC ⊥ BD
What conclusion can be drawn from part of given figure, if DC is the bisector of ∠ADB, CA ⊥ DA and CB ⊥ DB?
