Advertisements
Advertisements
प्रश्न
An electron jumps from fourth to first orbit in an atom. How many maximum number of spectral lines can be emitted by the atom? To which series these lines correspond?
Advertisements
उत्तर
When an electron passes from n = 4 energy level to n = 1 level, the number of maximum spectral lines emitted by the atom will be 6 because maximum number of photons emitted are 6, corresponding to 6 transitions. These lines will correspond to Balmer series.
APPEARS IN
संबंधित प्रश्न
In Balmer series, wavelength of first line is 'λ1' and in Brackett series wavelength of first line is 'λ2' then `lambda_1/lambda_2` is ______.
Let the series limit for Balmer series be 'λ1' and the longest wavelength for Brackett series be 'λ2'. Then λ1 and λ2 are related as ______.
The energy (in eV) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is ____________.
Each element is associated with a ______.
Continuous spectrum is produced by ______.
Absorption line spectrum is obtained ______.
Determine the shortest wavelengths of Balmer and Pasch en series. Given the limit for the Lyman series is 912 Å.
The first three spectral lines of H-atom in the Balmer series are given λ1, λ2, λ3 considering the Bohr atomic model, the wavelengths of the first and third spectral lines `(lambda_1/lambda_3)` are related by a factor of approximately 'x' × 10–1. The value of x, to the nearest integer, is ______.
The frequencies for series limit of Balmer and Paschen series respectively are 'v1' and 'v3'. If frequency of first line of Balmer series is 'v2' then the relation between 'v1', 'v2' and 'v3' is ______.
In the hydrogen atoms, the transition from the state n = 6 to n = 1 results in ultraviolet radiation. Infrared radiation will be obtained in the transition.
