मराठी

Use De-broglie'S Hypothesis to Write the Relation for the Nth Radius of Bohr Orbit in Terms of Bohr'S Quantization Condition of Orbital Angular Momentum? - Physics

Advertisements
Advertisements

प्रश्न

Use de-Broglie's hypothesis to write the relation for the nth radius of Bohr orbit in terms of Bohr's quantization condition of orbital angular momentum ?

Advertisements

उत्तर

According to Bohr’s postulates, 

\[mvr = \frac{nh}{2\pi}\]   ...... (1)

(where mvr = angular momentum of an electron and n is an integer).

Thus, the centripetal force,

\[\frac{m v^2}{r}\] (experienced by the electron) is due to the electrostatic attraction, 

\[\frac{kZ e^2}{r^2}\].

Where,
Z = Atomic number

Therefore, 

\[\frac{m v^2}{r} = \frac{kZ e^2}{r^2}\].

Substituting the value of v2 from (1), we obtain:

\[\frac{m}{r}\frac{n^2 h^2}{4 \pi^2 m^2 r^2} = \frac{kZ e^2}{r^2}\]

\[\therefore r = \frac{n^2 h^2}{4 \pi^2 mkZ e^2}\]

The relation for the nth radius of Bohr orbit in terms of Bohr's quantization condition of orbital angular momentum

\[= \frac{n^2 h^2}{4 \pi^2 mkZ e^2}\].
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2015-2016 (March) Foreign Set 2

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Calculate the de Broglie wavelength of an electron moving with - of the speed of light in vacuum (Negelct relativistic effect)

(Planck's constant: h = 6.63 x 10-34 Js, Mass of electron : m = 9.11 x 10-28 g)


A proton and an α-particle have the same de-Broglie wavelength. Determine the ratio of their accelerating potentials


Calculate the de-Broglie wavelength of an electron moving with one-fifth of the speed of light.Neglect relativistic effects. (`h = 6.63 xx 10^(-34)` J.s, c= `3xx10^8`m/s, mass of electron = `9 xx 10^(-31) kg)`


A proton and an electron have same kinetic. Which one has greater de-Broglie wavelength and why?


A proton and an electron have same velocity. Which one has greater de-Broglie wavelength and why?


Using de Broglie’s hypothesis, explain with the help of a suitable diagram, Bohr’s second postulate of quantization of energy levels in a hydrogen atom.


An electron, an alpha particle and a proton have the same kinetic energy.

Which one of these particles has the largest de-Broglie wavelength? 


Consider the de-Broglie wavelength of an electron and a proton. Which wavelength is smaller if the two particles have (a) the same speed (b) the same momentum (c) the same energy?


Light of wavelength 2000 Å falls on a metal surface of work function 4.2 eV.

What is the kinetic energy (in eV) of the fastest electrons emitted from the surface?


The de- Broglie wave length of an electron moving with a speed of 6.6 × 105 m/s is approximately


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×