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Calculate the wavelength of the first two lines in the Balmer series of hydrogen atoms. - Physics

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प्रश्न

Calculate the wavelength of the first two lines in the Balmer series of hydrogen atoms.

संख्यात्मक
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उत्तर

For Balmer series,

n = 2, m = 3, 4, 5, ....

(a) For first line in Balmer series, n = 2, m = 3

`1/lambda_1 = R_H(1/n^2 - 1/m^2)`

= `R_H (1/(2)^2 - 1/(3)^3)`

= `R_H (1/4 - 1/9)`

∴ `1/lambda_1 = R_H5/36`

∴ `lambda_1 = 36/(5 R_H)`

Putting RH = 1.097 × 107 m−1

∴ `lambda = 36/(5 xx 1.097 xx 10^7)`

= `(36 xx 10^-7)/5.485`

= 6.563 × 10−7 m

= 6563 Å

(b) For the second line in Balmer series, n = 2, m = 4

∴ `1/lambda_2 = R_H(1/(2)^2 - 1/(4)^2)`

= `R_H (1/4 - 1/16)`

∴ `1/lambda_2 = R_H3/16`

∴ `lambda_2 = 16/(3 R_H)`

= `16/(3 xx 1.097 xx 10^7)`

= `16/3.291 xx 10^-7`

= 4.862 × 10−7 m

= 4862 Å

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