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A uniform disc of radius R, is resting on a table on its rim.The coefficient of friction between disc and table is µ (Figure).

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प्रश्न

A uniform disc of radius R, is resting on a table on its rim.The coefficient of friction between disc and table is µ (Figure). Now the disc is pulled with a force F as shown in the figure. What is the maximum value of F for which the disc rolls without slipping?

दीर्घउत्तर
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उत्तर

Let the acceleration of the centre of mass of the disc be ‘a’, then

`Ma = F - f`   ......(1)

The angular acceleration of the disc is `α = a/R`. (if there is no sliding).

Then `(1/2 MR^2)α = Rf`  ......(2)


⇒ `Ma = 2f`

Thus, `f = F/3`. Since there is no sliding,

⇒ `f ≤ µmg`

⇒ `F ≤ 3µMg`.

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पाठ 7: System of Particles and Rotational Motion - Exercises [पृष्ठ ५६]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 7 System of Particles and Rotational Motion
Exercises | Q 7.28 | पृष्ठ ५६

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