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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

A system releases 130 kJ of heat while 109 kJ of work is done on the system. Calculate the change in internal energy.

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प्रश्न

A system releases 130 kJ of heat while 109 kJ of work is done on the system. Calculate the change in internal energy.

संख्यात्मक
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उत्तर

Data: Q = −130 kJ, W = −109 kJ

Find: ΔU = ?

Calculations:

ΔU = Q − W

ΔU = −130 − (−109)

ΔU = −130 + 109

ΔU = −21 kJ

∴ The change in internal energy is −21 kJ. This is the change (decrease) in the internal energy.

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पाठ 4: Thermodynamics - Exercises [पृष्ठ १०८]

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