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A Monochromatic Light Source of Intensity 5 Mw Emits 8 × 1015 Photons per Second. this Light Ejects Photoelectrons from a Metal Surface. the Stopping Potential for this Setup is 2.0 V. - Physics

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प्रश्न

A monochromatic light source of intensity 5 mW emits 8 × 1015 photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this setup is 2.0 V. Calculate the work function of the metal.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)

एक शब्द/वाक्यांश उत्तर
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उत्तर

Given:-

Intensity of light, I = 5 mW

Number of photons emitted per second, n = 8 × 1015

Stopping potential, V0 = 2 V

Energy, `E = hv = I/n = (5 xx 10^-3)/(8 xx 10^15)`

From Einstein's photoelectric equation, work function,

`W_0 = hv - eV_0`

Here, h = Planck's constant

`e = 1.6 xx 10^-19 C`

On substituting the respective values, we get :-

`W_0 = (5 xx 10^-3)/(8 xx 10^15) - 1.6 xx 10^-19 xx 2`

`= 6.25 xx 10^-19 - 3.2 xx 10^-19`

`= 3.05 xx 10^-19`

`= (3.05 xx 10^-19)/(1.6 xx 10^-15) = 1.906  "eV"`

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Einstein’s Photoelectric Equation: Energy Quantum of Radiation
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पाठ 20: Photoelectric Effect and Wave-Particle Duality - Exercises [पृष्ठ ३६६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 20 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 23 | पृष्ठ ३६६

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