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The photon emitted during the de-excitation from the first excited level to the ground state of a hydrogen atom is used to irradiate a photocathode in which the stopping potential is 5 V. - Physics

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प्रश्न

The photon emitted during the de-excitation from the first excited level to the ground state of a hydrogen atom is used to irradiate a photocathode in which the stopping potential is 5 V. Calculate the work function of the cathode used.

संख्यात्मक
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उत्तर

In the photoelectric effect, stopping potential is directly proportional to the maximum kinetic energy of the emitted electron.

This maximum kinetic energy is further dependent on the frequency of incident light as well as the work function of the cathode. Combining both these facts, we can arrive at the work function of the cathode used.

KE = hν - Φ0

Where, hν = E2 - E1

= `(-13.6)/2^2 - (-13.6)/1^2`

= `3/4 xx 13.6 = 10.2` eV

eV = hν - Φ0

`5V xx e = 10.2  eV - phi_0`

Φ= 5.2 eV

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Einstein’s Photoelectric Equation: Energy Quantum of Radiation
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2022-2023 (March) Delhi Set 2

संबंधित प्रश्‍न

Write Einstein’s photoelectric equation?


Briefly explain the three observed features which can be explained by Einstein’s photoelectric equation.


Define the terms (i) ‘cut-off voltage’ and (ii) ‘threshold frequency’ in relation to the phenomenon of photoelectric effect.

Using Einstein’s photoelectric equation shows how the cut-off voltage and threshold frequency for a given photosensitive material can be determined with the help of a suitable plot/graph.


The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


In a photoelectric experiment, the collector plate is at 2.0 V with respect to the emitter plate made of copper (φ = 4.5 eV). The emitter is illuminated by a source of monochromatic light of wavelength 200 nm. Find the minimum and maximum kinetic energy of the photoelectrons reaching the collector.


The minimum energy required to remove an electron is called ______.


  1. In the explanation of photo electric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the equation for the maximum energy Emax of the emitted electron as Emax = hν – φ where φ0 is the work function of the metal. If an electron absorbs 2 photons (each of frequency ν) what will be the maximum energy for the emitted electron?
  2. Why is this fact (two photon absorption) not taken into consideration in our discussion of the stopping potential?

A student performs an experiment on photoelectric effect, using two materials A and B. A plot of Vstop vs ν is given in Figure.

  1. Which material A or B has a higher work function?
  2. Given the electric charge of an electron = 1.6 × 10–19 C, find the value of h obtained from the experiment for both A and B.

Comment on whether it is consistent with Einstein’s theory:


A photon of wavelength 663 nm is incident on a metal surface. The work function of the metal is 1.50 eV. The maximum kinetic energy of the emitted photoelectrons is ______.


If c is the velocity of light in free space, the correct statements about photon among the following are:

  1. The energy of a photon is E = hv.
  2. The velocity of a photon is c.
  3. The momentum of a photon, ρ = `(h v)/c`
  4. In a photon-electron collision, both total energy and total momentum are conserved.
  5. Photon possesses positive charge.

Choose the correct answer from the options given below:


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