मराठी

A man accepts a position with an initial salary of Rs 5200 per month. It is understood that he will receive an automatic increase of Rs 320 in the very next month and each month thereafter

Advertisements
Advertisements

प्रश्न

A man accepts a position with an initial salary of Rs 5200 per month. It is understood that he will receive an automatic increase of Rs 320 in the very next month and each month thereafter. Find his salary for the tenth month

बेरीज
Advertisements

उत्तर

Given that fixed increment in the salary of a man

= Rs. 320 each month

Initial salary = Rs. 5200 which makes an A.P

whose first term (a) = Rs. 5200 and common difference (d) = Rs. 320

Salary for the tenth month 

a10 = a + (n – 1)d

= 5200 + (10 – 1) × 320

= 5200 + 2880

= Rs. 8080

Hence, the required amount is Rs. 8080

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Sequences and Series - Exercise [पृष्ठ १६१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 9 Sequences and Series
Exercise | Q 3.(i) | पृष्ठ १६१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

if `(a^n + b^n)/(a^(n-1) + b^(n-1))` is the A.M. between a and b, then find the value of n.


A farmer buys a used tractor for Rs 12000. He pays Rs 6000 cash and agrees to pay the balance in annual installments of Rs 500 plus 12% interest on the unpaid amount. How much will be the tractor cost him?


A sequence is defined by an = n3 − 6n2 + 11n − 6, n ϵ N. Show that the first three terms of the sequence are zero and all other terms are positive.


Show that the following sequence is an A.P. Also find the common difference and write 3 more terms in case.

−1, 1/4, 3/2, 11/4, ...


Which term of the A.P. 84, 80, 76, ... is 0?


If (m + 1)th term of an A.P. is twice the (n + 1)th term, prove that (3m + 1)th term is twice the (m + n + 1)th term.


An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.


The sum of 4th and 8th terms of an A.P. is 24 and the sum of the 6th and 10th terms is 34. Find the first term and the common difference of the A.P.


\[\text { If } \theta_1 , \theta_2 , \theta_3 , . . . , \theta_n \text { are in AP, whose common difference is d, then show that }\]

\[\sec \theta_1 \sec \theta_2 + \sec \theta_2 \sec \theta_3 + . . . + \sec \theta_{n - 1} \sec \theta_n = \frac{\tan \theta_n - \tan \theta_1}{\sin d} \left[ NCERT \hspace{0.167em} EXEMPLAR \right]\]


Find the sum of the following arithmetic progression :

1, 3, 5, 7, ... to 12 terms


Find the sum of the following arithmetic progression :

 (x − y)2, (x2 + y2), (x + y)2, ... to n terms


Find the sum of the following serie:

(a − b)2 + (a2 + b2) + (a + b)2 + ... + [(a + b)2 + 6ab]


Find the sum of first n natural numbers.


Find the sum of all integers between 100 and 550, which are divisible by 9.


Find the sum of the series:
3 + 5 + 7 + 6 + 9 + 12 + 9 + 13 + 17 + ... to 3n terms.


Solve: 

25 + 22 + 19 + 16 + ... + x = 115


The number of terms of an A.P. is even; the sum of odd terms is 24, of the even terms is 30, and the last term exceeds the first by \[10 \frac{1}{2}\] , find the number of terms and the series. 


How many terms of the A.P. −6, \[- \frac{11}{2}\], −5, ... are needed to give the sum −25?


If S1 be the sum of (2n + 1) terms of an A.P. and S2 be the sum of its odd terms, then prove that: S1 : S2 = (2n + 1) : (n + 1).


Find an A.P. in which the sum of any number of terms is always three times the squared number of these terms.


If the sum of n terms of an A.P. is nP + \[\frac{1}{2}\] n (n − 1) Q, where P and Q are constants, find the common difference.


The sums of first n terms of two A.P.'s are in the ratio (7n + 2) : (n + 4). Find the ratio of their 5th terms.


If a, b, c is in A.P., then show that:

bc − a2, ca − b2, ab − c2 are in A.P.


If \[\frac{b + c}{a}, \frac{c + a}{b}, \frac{a + b}{c}\] are in A.P., prove that:

 bc, ca, ab are in A.P.


A man arranges to pay off a debt of Rs 3600 by 40 annual instalments which form an arithmetic series. When 30 of the instalments are paid, he dies leaving one-third of the debt unpaid, find the value of the first instalment.


A piece of equipment cost a certain factory Rs 600,000. If it depreciates in value, 15% the first, 13.5% the next year, 12% the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?


If log 2, log (2x − 1) and log (2x + 3) are in A.P., write the value of x.


If the sum of p terms of an A.P. is q and the sum of q terms is p, then the sum of p + q terms will be


If the sum of n terms of an A.P. be 3 n2 − n and its common difference is 6, then its first term is


If a1, a2, a3, .... an are in A.P. with common difference d, then the sum of the series sin d [sec a1 sec a2 + sec a2 sec a3 + .... + sec an − 1 sec an], is


If n arithmetic means are inserted between 1 and 31 such that the ratio of the first mean and nth mean is 3 : 29, then the value of n is


If, S1 is the sum of an arithmetic progression of 'n' odd number of terms and S2 the sum of the terms of the series in odd places, then \[\frac{S_1}{S_2}\] = 


Mark the correct alternative in the following question:

\[\text { If in an A . P } . S_n = n^2 q \text { and } S_m = m^2 q, \text { where } S_r \text{ denotes the sum of r terms of the A . P  . , then }S_q \text { equals }\]


If abc are in G.P. and a1/b1/y = c1/z, then xyz are in


The product of three numbers in A.P. is 224, and the largest number is 7 times the smallest. Find the numbers


If a1, a2, ..., an are in A.P. with common difference d (where d ≠ 0); then the sum of the series sin d (cosec a1 cosec a2 + cosec a2 cosec a3 + ...+ cosec an–1 cosec an) is equal to cot a1 – cot an 


If the sum of p terms of an A.P. is q and the sum of q terms is p, show that the sum of p + q terms is – (p + q). Also, find the sum of first p – q terms (p > q).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×