मराठी

If a ( 1 B + 1 C ) , B ( 1 C + 1 a ) , C ( 1 a + 1 B ) Are in A.P., Prove that A, B, C Are in A.P. - Mathematics

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प्रश्न

If \[a\left( \frac{1}{b} + \frac{1}{c} \right), b\left( \frac{1}{c} + \frac{1}{a} \right), c\left( \frac{1}{a} + \frac{1}{b} \right)\] are in A.P., prove that abc are in A.P.

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उत्तर

Given:

\[a\left( \frac{1}{b} + \frac{1}{c} \right), b\left( \frac{1}{c} + \frac{1}{a} \right), c\left( \frac{1}{a} + \frac{1}{b} \right)\]  are in A.P.

\[\text { By adding 1 to each term, we get }: \]

\[ a\left( \frac{1}{b} + \frac{1}{c} \right) + 1, b\left( \frac{1}{c} + \frac{1}{a} \right) + 1, c\left( \frac{1}{a} + \frac{1}{b} \right) + 1 \text { are in A . P } . \]

\[ \Rightarrow a\left( \frac{1}{b} + \frac{1}{c} + \frac{1}{a} \right), b\left( \frac{1}{c} + \frac{1}{a} + \frac{1}{b} \right), c\left( \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \right) \text { are in A . P } . \]

\[\text { Dividing all terms by } \frac{1}{a} + \frac{1}{b} + \frac{1}{c}, \text { we get }: \]

\[ \Rightarrow \text { a, b, c are in A . P } . \]

\[\text { Hence, proved } .\]

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पाठ 19: Arithmetic Progression - Exercise 19.5 [पृष्ठ ४२]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 19 Arithmetic Progression
Exercise 19.5 | Q 6 | पृष्ठ ४२

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