मराठी

The Sum of the First Four Terms of an A.P. is 56. the Sum of the Last Four Terms is 112. If Its First Term is 11, Then Find the Number of Terms. - Mathematics

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प्रश्न

The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms.

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उत्तर

Let the A.P. be aa + da + 2da + 3d, ... a + (n – 2) da + (n – 1)d.

Sum of first four terms = a + (a + d) + (a + 2d) + (a + 3d) = 4a + 6d

Sum of last four terms = [a + (n – 4) d] + [a + (n – 3) d] + [a + (n – 2) d]

+ [a + n – 1) d]

= 4a + (4n – 10) d

According to the given condition,

4a + 6d = 56

⇒ 4(11) + 6d = 56 [Since a = 11 (given)]

⇒ 6d = 12

⇒ d = 2

∴ 4a + (4n –10) d = 112

⇒ 4(11) + (4n – 10)2 = 112

⇒ (4n – 10)2 = 68

⇒ 4n – 10 = 34

⇒ 4n = 44

⇒ n = 11

Thus, the number of terms of the A.P. is 11.

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पाठ 9: Sequences and Series - Miscellaneous Exercise [पृष्ठ १९९]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 9 Sequences and Series
Miscellaneous Exercise | Q 12 | पृष्ठ १९९

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