Advertisements
Advertisements
प्रश्न
A light metal disc on the top of an electromagnet is thrown up as the current is switched on. Why? Give reason.
Advertisements
उत्तर
When the current begins to grow through the electromagnet, the magnetic flux through the disc begins to increase. This sets up eddy current in the disc in the same direction as that of the electromagnetic current. Thus, if the upper surface of electromagnet acquires N-polarity, the lower surface of the disc also acquires N-polarity. As same magnetic poles repel each other, the light metallic disc is thrown up.
APPEARS IN
संबंधित प्रश्न
A circular coil of cross-sectional area 200 cm2 and 20 turns is rotated about the vertical diameter with angular speed of 50 rad s−1 in a uniform magnetic field of magnitude 3.0 × 10−2T. Calculate the maximum value of the current in the coil.
State three ways in which the strength of an electromagnet can be increased.
Explain why, an electromagnet is called a temporary magnet.
The most suitable material for making the core of an electromagnet is:
(a) soft iron
(b) brass
(c) aluminium
(d) steel
A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field Bexists along the perpendicular to the plane of the loop as shown in figure. The current induced in the loop is _____________ .

Write the two names in the following diagram.
Fleming’s right hand rule.

An electron moves on a straight-line path XY as shown in the figure. The coil abcd is adjacent to the path of the electron. What will be the direction of the current, if any, induced in the coil?

What for an inductor is used? Give some examples.
What should be the core of an electromagnet?
A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure

Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field `vec"B"` pointing into the page. An external agent pulls the bar to the left at a constant speed v. The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is:
