Advertisements
Advertisements
प्रश्न
A car covers 90 km in `1 1/2` hours towards east. Calculate
- displacement of car,
- its velocity in (a) kmh−1 (b) ms−1.
Advertisements
उत्तर
(i) A car covers 90 km in `1 1/2` hour i.e. `3/2` hour towards east.
∴ Displacement = 90 km − east
(ii) Time = `1 1/2` hour = `3/2` hour
Velocity = `"Displacement"/"Time"`
v = `90/(3//2)`
v = `(90xx2)/3` = 60 km/h
v = `60xx1000/3600` m/s
v = `100/6` m/s = 16.67 ms−1
APPEARS IN
संबंधित प्रश्न
Under what conditions can a body travel a certain distance and yet its resultant displacement be zero ?
A body travels a distance of 3 km towards East, then 4 km towards North and finally 9 km towards East.
What is the resultant displacement ?
A particle is moving in a circular path of radius r. The displacement after half a circle would be :
In which of the following cases of motion, the distance moved and the magnitude of displacement are equal?
Can displacement be zero even if the distance is not zero? Give one example to explain your answer.
From the displacement – time graph shown given below calculate:
- Average velocity in the first three seconds.
- Displacement from the initial position at the end of 13 s.
- Time after which the body is at the initial position,
- Average velocity after 8 s.
Show the difference between distance and displacement with the help of a diagram.
Calculate the distance and displacement in the following case:
An object covers a distance of S meters in t seconds as follows :
| S (meters) | 0 | 8 | 20 | 20 | 16 | 10 | 0 |
| t (Seconds) | 80 | 2 | 5 | 10 | 12 | 15 | 10 |
Plot a graph, taking t on X-axis and S on Y-axis. Determine the velocity of the object at time
(i) 6 s, and
(ii) 14 s.
Displacement magnitude can be greater than the distance traveled by the object.
