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प्रश्न
A body travels a distance of 3 km towards East, then 4 km towards North and finally 9 km towards East.
What is the resultant displacement ?
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उत्तर
The body travels a total distance of 12 km east, which means towards the x-axis, on a Cartesian plane. It travels a distance of 4 km in north direction, which means towards y-axis.
Resultant displacement :
`sqrt(12^2+4^2)`
= `sqrt(144 + 16)`
= `sqrt(160)`
= 12.65 km
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संबंधित प्रश्न
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- It cannot be zero.
- Its magnitude is greater than the distance travelled by the object.
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Define displacement. State its unit.
Can displacement be zero even if the distance is not zero? Give one example to explain your answer.
State how the velocity-time graph can be used to find The displacement of the body in a given time.
A body at rest is made to fall from the top of a tower. Its displacement at different instants is given in the following table:
| Time (in s) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 |
| Displacement (in m) | 0.05 | 0.20 | 0.45 | 0.80 | 1.25 | 1.80 |
Draw a displacement-time graph and state whether the motion is uniform or non-uniform?
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