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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?

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प्रश्न

A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?

संख्यात्मक
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उत्तर

It is given that the energy of the electron beam used to bombard gaseous hydrogen at room temperature is 12.5 eV. Also, the energy of the gaseous hydrogen in its ground state at room temperature is −13.6 eV.

When gaseous hydrogen is bombarded with an electron beam, the energy of the gaseous hydrogen becomes −13.6 + 12.5 eV i.e., −1.1 eV.

Orbital energy is related to orbit level (n) as:

E = `(-13.6)/(n)^2 ev`

For n = 3, E = `(-13.6)/9` = −1.5 eV

This energy is approximately equal to the energy of gaseous hydrogen. It can be concluded that the electron has jumped from n = 1 to n = 3 level.

During its de-excitation, the electrons can jump from n = 3 to n = 1 directly, which forms a line of the Lyman series of the hydrogen spectrum.

We have the relation for wave number for the Lyman series as:

`1/lambda = R_y (1/1^2 - 1/n^2)`

Where

Ry = Rydberg constant = 1.097 × 107 m−1

λ = Wavelength of radiation emitted by the transition of the electron

For n = 3, we can obtain λ as:

`1/lambda = 1.0997 xx 10^7 (1/1^2 - 1/3^2)`

= `1.097 xx 10^7 (1 - 1/9)`

= `1.097 xx 10^7 xx 8/9`

`lambda = 9/(8 xx 1.097 xx 10^7)`

= 102.55 nm

If the electron jumps from n = 2 to n = 1, then the wavelength of the radiation is given as:

`1/lambda = 1.097 xx 10^7 (1/1^2 - 1/2^2)`

= `1.097 xx 10^7(1- 1/4)`

= `1.097 xx 10^7 xx 3/4`

`lambda = 4/(1.097 xx 10^7 xx 3)`

= 121.54 nm

If the transition takes place from n = 3 to n = 2, then the wavelength of the radiation is given as:

`1/lambda = 1.097 xx 10^7 (1/2^2 - 1/3^2)`

`= 1.097 xx 10^7 (1/4 - 1/9)`

= `1.097 xx 10^7 xx 5/36`

= `36 /(5xx1.097 xx 10^7)`

= 656.33 nm

This radiation corresponds to the Balmer series of the hydrogen spectrum.

Hence, in the Lyman series, two wavelengths, i.e., 102.55 nm and 121.54 nm, are emitted. And in the Balmer series, one wavelength, i.e., 656.33 nm, is emitted.

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पाठ 12: Atoms - EXERCISES [पृष्ठ ३०५]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 12 Atoms
EXERCISES | Q 12.8 | पृष्ठ ३०५
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 12 Atoms
Exercise | Q 12.9 | पृष्ठ ४३६

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